That strtotime is a neat little command. With a bit more searching I found that this works:
$expiry_date = strtotime("+21 days"); $expiry_date = date('Y-m-d', $expiry_date); echo $expiry_date; The computer couldn't cope with me doing it in just one line --- I got a parse error. Ron ----- Original Message ----- From: Calvin Lough <[EMAIL PROTECTED]> To: Ron Piggott <[EMAIL PROTECTED]>; PHP DB <php-db@lists.php.net> Sent: Wednesday, March 02, 2005 10:50 AM Subject: Re: [PHP-DB] Expiry Date ($date function) > The strtotime function should work the best. > > $add_twentyone = strtotime("+21 days"); > > I dont know if that will work or not. I just found that method in the > php doc and it looked interesting. Hopefully it will work for you. > > Calvin > > On Wed, 2 Mar 2005 04:41:04 -0500, Ron Piggott > <[EMAIL PROTECTED]> wrote: > > I figured out that the syntax below creates the date in the way it may be > > stored in a mySQL table: > > > > $todays_date=DATE('Y-m-d'); > > > > Is there any way to add 21 days to this as an expiry date? For example if > > the date was March 20th 2005 21 days would be in April --- is there any way > > of dealing with this? > > > > Ron > > > > -- > > PHP Database Mailing List (http://www.php.net/) > > To unsubscribe, visit: http://www.php.net/unsub.php > > > > > -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php