Chris Carter wrote:
I have a field in database called "logos" which has one value
"images/logos/some_logo.jpg"
In my php I am trying to call it in my php file as image. With this code.
$sno = $_REQUEST['sno'];
$query="SELECT logos FROM table WHERE sno = '$sno'";
Please please please read http://www.phpsec.org/
particularly
http://phpsec.org/projects/guide/3.html#3.2
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