I was unsure what was meant by FILE in php - is that the global? How do
I reference a remote site's jpg file into FILE? Then how to I create
the output from the php into stdout - using the return of a function?
or print? Then how to launch rsynch - I understand how to call it from
cron, as my web server kindly gives me an interface for this, but to
create the file I would need to know what extension to save with the
script name, and how to make it execute, ie the equivalent of <?php for
rsynch scripts. Then how is FILE read by rsynch script. So lots more
questions just to copy a publicly available image into my site. There
has got to be an easier way.
Mr Webber wrote:
Note the rsync option:
This option is related to the --include option, but it specifies
a FILE that contains include patterns (one per line). Blank
lines in the file and lines starting with ';' or '#' are ignored. If
FILE is -, the list will be read from standard input.
So, from a PhpScript, you manage the contents of "FILE" and then launch
rsync with the appropriate additional options.
From: ioannes [mailto:[EMAIL PROTECTED]
Sent: Monday, February 04, 2008 12:59 PM
Subject: Re: [PHP-DB] Copying an image from one server to another
Initially I could not find much on SCP and rsynch is about synchronising
folders, but that is only part of the problem. I don't want files in
the target location that are not referenced from the target database. I
hold references like this
then I parse it out into the img array.
So I want to do it from php programming and am on a shared server. I
may have access to the terminal for linux/unix but I am not too strong
in that area. So am I wrong to be still thinking of cURL?
Aleksandar Vojnovic wrote:
How about sending the file via SCP? (it would be a much more safer to
I am trying to:
- check whether an image file exists on a server,
- check whether it does not exist on another server, and if not exists
- to copy from the first location to the second.
I am using cURL. First step to capture the image from the first
server. When I return this image to the browser I get a lot of
strange characters. So has this captured the image and what do I
use next to upload to the second server?
I was trying to use file_exists and had problems referencing the
file location as "http://wwww.mysite.com/pic.jpg". But I know I can
also look at using readfile() and file_put_contents(), $fp =
fopen(), fputs(), fpassthru() etc. What is best way?
There's no way fopen is going to be able to write to a remote url,
that'd just be such a huge security issue it's not funny.
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