What if you use back-quotes `` around the table/view name?
$stmt = OCIParse($conn, "SELECT * FROM `v$sql`");
----- Original Message -----
From: <n.a.mor...@bton.ac.uk>
To: "Mark Casson" <confu...@icube.co.uk>; <php-db@lists.php.net>
Sent: Thursday, April 23, 2009 5:25 AM
Subject: RE: [PHP-DB] PHP and table/view names with '$'
I find that using single quotes rather than double quotes prevents
variable substitution.
I don't know if this is an undocumented feature, as the documentation
says that both have the same functionality.
Regards,
Neil
-----Original Message-----
From: Mark Casson [mailto:confu...@icube.co.uk]
Sent: 23 April 2009 11:04
To: php-db@lists.php.net
Subject: [PHP-DB] PHP and table/view names with '$'
Hi,
I am trying to access some of the v$ views using php on iis, with admin
privileges.
However, using:
$stmt = OCIParse($conn, "SELECT * FROM v$sql");
gives me this error:
PHP Notice: undefined variable: sql . . .
Is there a way around this?
Thanks
Mark
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