On 9/19/2012 3:12 PM, Jim Giner wrote:
Continuing on - why is your visual structure at this point NOT the same
as your physical structure? I don't think you're telling us what your
real problem is here. We need more information. You have '15 row with
3 cols each', ie, 'each row has 3 values'. So - your table has 15
records in it, each with 3 columns. Add a key field to give each row an
identity and that's it. No?
On 9/18/2012 8:52 AM, Bruno Sandivilli wrote:
Hi, i strugling to decide what is the best choice:
I have a 15 row x 3 columns Flash DataGrid, it means, for each row i
To represent this in my Database, I could:
1. Create 2 Tables : A Values table - with 3 columns ; and a Bill
(with 15 foreign keys, each one pointing to one row in the Values
2. Create one Table with 45 columns (15 fields * 3 values for each
I want to know, wich is the best choice?
To manage my query, now i have a SELECT with a thousand of leftJoins.
This is the best choice?
How could I run a query wich will give all results linked, like:
( column_1_val_1, column_1_val_2, column_1_val_2,
column_2_val_1, column_1_val_2, column_1_val_3,
I don't get it either.
You have 15 rows with 3 cols each. So? Display them. Query them. Big
What is the real difficulty here? I'm not seeing it.
(I don't read it as 15x3x3 - at least that's not what he said since he
said 'for each row he has 3 values')
Sorry - but again - this post is not showing me a clear problem.
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