ID: 10529
Updated by: andi
Reported By: [EMAIL PROTECTED]
Old-Status: Open
Status: Closed
Bug Type: Unknown/Other Function
PHP Version: 4.0.4pl1
Assigned To:
Comments:
This happens because PHP works on strings and the increment of "Z" as a string is
"AA". "AA" is smaller than "Z".
Andi
Previous Comments:
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[2001-04-27 16:05:57] [EMAIL PROTECTED]
I agree the code was a bit strange, but I found it weird that it worked with any
letter but Z.
The suggested code worked. Thanks!
---------------------------------------------------------------------------
[2001-04-27 15:23:07] [EMAIL PROTECTED]
I'm not even sure that is supposed to work like that. Guys?
Why don't you use this instead?
for ($i = ord('A'); $i <= ord('Z'); $i++) {
echo chr($i)."<br>";
}
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[2001-04-27 15:06:25] [EMAIL PROTECTED]
Trying to make a script that showed the letters from A to Z using the following code:
for ($i = 'A'; $i <= 'Z'; $i++) {
echo "$i<br>";
}
I saw that the script outputted the first letters (A-Z) but then it started to display
AA, AB, AC [...] YZ.
Replacing the 'Z' above to 'Y' (or any other letter between B and Y) makes the script
show correctly the letters from A to that letter.
Replacing letters to lowercase and/or single quotation marks to double causes the same
error.
This happened both in PHP 4.0.4pl1 under Windows and in PHP 4.0.1pl1 under Linux.
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