ID: 10668
User Update by: [EMAIL PROTECTED]
Status: Analyzed
Bug Type: PCRE related
Description: preg_replace backquote failure
Oddly, I get the following error:
Warning: Unexpected character in input: '\' (ASCII=92) state=1 in
/home/groups/t/ta/tavi/htdocs/playground/test.php(4) : regexp code on line 1
Parse error: parse error in /home/groups/t/ta/tavi/htdocs/playground/test.php(4) :
regexp code on line 1
Fatal error: Failed evaluating code: f('\'\\\\'\'') in
/home/groups/t/ta/tavi/htdocs/playground/test.php on line 4
PHP compile options may be seen at:
http://tavi.sourceforge.net/playground/phpinfo.php
Previous Comments:
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[2001-05-04 12:58:12] [EMAIL PROTECTED]
Can you explain why you think it fails? The following sample (slightly modified from
yours to dump the $s parameter to function):
$str = "abc'\\''def";
function f($s) { var_dump($s); return "x"; }
print preg_replace("/c(.*)d/e", "f('\1')", $str);
outputs:
string(5) "'\''"
abxef
As it should.
---------------------------------------------------------------------------
[2001-05-04 11:44:19] [EMAIL PROTECTED]
The following code succeeds on PHP 4.03 and PHP 4.04pl1, but fails on PHP 4.05:
$str = "abc'\\''def";
function f($s) { return "x"; }
print preg_replace("/c(.*)d/e", "f('\1')", $str, -1);
This seems to expose *two* underlying bugs:
1) There appears to be some problem in the regex state
machine
2) There is a definite problem with the replacement of
the backreference with its corresponding string.
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Full Bug description available at: http://bugs.php.net/?id=10668
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