ID: 11555 Updated by: derick Reported By: [EMAIL PROTECTED] Old-Status: Open Status: Closed Bug Type: Feature/Change Request Operating system: PHP Version: 4.0.5 Assigned To: Comments: You can use the strftime function already, it's the %W modifier. But it would be useful if date would support it indeed. Previous Comments: --------------------------------------------------------------------------- [2001-06-20 04:44:17] [EMAIL PROTECTED] i live in sweden, where displaying weeknumbers in calendars of any sort is common. the following code does the work, tho i'd be very happy if it could be supported to be returned from the date() function. switch(date("w",mktime(0,0,0,$mon,$daycnt+1,$year))) { case 1: $daysub=0; break; case 2: $daysub=1; break; case 3: $daysub=2; break; case 4: $daysub=3; break; case 5: $daysub=4; break; case 6: $daysub=5; break; case 0: $daysub=6; break; } $weeknumber=round((date("z", mktime(0,0,0, date("m"),date("d")+1-$daysub,date("Y")))+7)/7); if($weeknumber==53) { //some years have 53 weeks & some 52 //so we check next weeks weeknumber, if its 1 this is week 53, otherwise, this is week 1. switch(date("w",mktime(0,0,0,date("m"),date("d")+8,date("Y")))) { case 1: $daysub=0; break; case 2: $daysub=1; break; case 3: $daysub=2; break; case 4: $daysub=3; break; case 5: $daysub=4; break; case 6: $daysub=5; break; case 0: $daysub=6; break; } $tmpweeknumber=round( (date("z", mktime(0,0,0, date("m"), date("d")+8-$daysub, date("Y")))+7)/7); if($tmpweeknumber==1) $weeknumber=53; else $weeknumber=1; } --------------------------------------------------------------------------- [2001-06-19 05:41:56] [EMAIL PROTECTED] i live in sweden, where displaying weeknumbers in calendars of any sort is common. the following code does the work, tho i'd be very happy if it could be supported to be returned from the date() function. the algorithm is (mondaynumber+7)/7 where mondaynumber is the day of the year of the monday of the current year switch(date("w")) { case 1: $daysub=0; break; case 2: $daysub=1; break; case 3: $daysub=2; break; case 4: $daysub=3; break; case 5: $daysub=4; break; case 6: $daysub=5; break; case 0: $daysub=6; break; } $weeknumber=(date ("z", mktime(0,0,0, date("m"), date("d")-$daysub, date("Y")) )+7)/7; --------------------------------------------------------------------------- ATTENTION! Do NOT reply to this email! To reply, use the web interface found at http://bugs.php.net/?id=11555&edit=2 -- PHP Development Mailing List <http://www.php.net/> To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]