ID: 11555
Updated by: cmv
Reported By: [EMAIL PROTECTED]
Old-Status: Open
Status: Closed
Bug Type: Feature/Change Request
Operating system:
PHP Version: 4.0.5
Assigned To: cmv
Comments:
date('W') has been added to CVS.
It returns the ISO 8601 week number (0-53). Basically, Monday is the first day of the
week, and week #1 of the year is the week that contains January 4.
- Colin
Previous Comments:
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[2001-06-20 11:56:17] [EMAIL PROTECTED]
Trouble is (I suppose), some week-of-year functions consider Monday the first day of
the week, and some consider Sunday.
I guess two switches in date() should be done. I'll work on this.
---------------------------------------------------------------------------
[2001-06-20 08:53:13] [EMAIL PROTECTED]
Not closed...
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[2001-06-20 08:52:32] [EMAIL PROTECTED]
You can use the strftime function already, it's the %W modifier.
But it would be useful if date would support it indeed.
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[2001-06-20 04:44:17] [EMAIL PROTECTED]
i live in sweden, where displaying weeknumbers in calendars of any sort is common. the
following code does the work, tho i'd be very happy if it could be supported to be
returned
from the date() function.
switch(date("w",mktime(0,0,0,$mon,$daycnt+1,$year))) {
case 1: $daysub=0; break;
case 2: $daysub=1; break;
case 3: $daysub=2; break;
case 4: $daysub=3; break;
case 5: $daysub=4; break;
case 6: $daysub=5; break;
case 0: $daysub=6; break;
}
$weeknumber=round((date("z", mktime(0,0,0,
date("m"),date("d")+1-$daysub,date("Y")))+7)/7);
if($weeknumber==53) {
//some years have 53 weeks & some 52
//so we check next weeks weeknumber, if its 1 this is week 53, otherwise, this
is week 1.
switch(date("w",mktime(0,0,0,date("m"),date("d")+8,date("Y")))) {
case 1: $daysub=0; break;
case 2: $daysub=1; break;
case 3: $daysub=2; break;
case 4: $daysub=3; break;
case 5: $daysub=4; break;
case 6: $daysub=5; break;
case 0: $daysub=6; break;
}
$tmpweeknumber=round( (date("z", mktime(0,0,0, date("m"), date("d")+8-$daysub,
date("Y")))+7)/7);
if($tmpweeknumber==1) $weeknumber=53;
else $weeknumber=1;
}
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[2001-06-19 05:41:56] [EMAIL PROTECTED]
i live in sweden, where displaying weeknumbers in calendars of any sort is common. the
following code does the work, tho i'd be very happy if it could be supported to be
returned from the date() function.
the algorithm is (mondaynumber+7)/7
where mondaynumber is the day of the year of the monday of the current year
switch(date("w")) {
case 1: $daysub=0; break;
case 2: $daysub=1; break;
case 3: $daysub=2; break;
case 4: $daysub=3; break;
case 5: $daysub=4; break;
case 6: $daysub=5; break;
case 0: $daysub=6; break;
}
$weeknumber=(date ("z", mktime(0,0,0, date("m"), date("d")-$daysub, date("Y")) )+7)/7;
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