ID: 12770
Updated by: kalowsky
Old Status: Open
Status: Bogus
Bug Type: ODBC related
Operating System: win98 with PWS
PHP Version: 4.0.6
New Comment:

okay this isn't a help forum, this is for reporting bugs 
within the PHP system.  as this bug is a request for help, 
marking as bogus.  if you have questions on how to use php 
you may wish to ask the php-general or php-database lists, 
or even ask on irc channels dedicated to PHP.

Previous Comments:

[2001-08-15 13:52:24] [EMAIL PROTECTED]

What i want to do is retrieve data from a table in access using odbc. I can retrieve 
info correctly, except from when i want to retrieve specific information.
I want to create a table on a webpage that retrieves a column of info, and uses this 
info to make a link. With this link there will be a querystring called id, and this 
comes from the ID field in my DB which i also have retrieved using my select 

So how do i use odbc_result and odbc_fetch_row together to achieve this. Or is there 
another method using ODBC that i dont have knowledge of.

Beneath is my code::

Thnx in advance

<TITLE>MXManiaWorld :: Tracks - Download</TITLE>
<STYLE TYPE="text/css">
TH {color: white; background-color: gray}
TD {background-color: silver; text : black }
<BODY bgcolor="navy" text="">

//retrieve data from DB and show in browser.
//Img, then at side details.

//Declare DB variables
$odbc_dsn = 'mxm_db';
$odbc_userid = '******';
$odbc_userpassword = '******';

if(!($odbc_db=odbc_connect("$odbc_dsn", "$odbc_userid", "$odbc_userpassword")))
die("Couldn't connect to odbc database - $odbc_dsn");


echo "<TABLE WIDTH='98%' border='1' bordercolor='#ffffff'>";

$query2 = "SELECT ID, FileName FROM tbl_uploads";

//submit query
if(!($odbc_rs2 = odbc_exec($odbc_db, $query2)))
die("Error executing query. Please inform the webmaster");




while($query_data = odbc_fetch_row($odbc_rs2)) {
$num_cols = odbc_num_fields($odbc_rs2);
for($a = 1; $a <= $num_cols; $a++) {

if(!($track_id = odbc_result($query2, $a)))
die("Couldn't get result");
if(!($tracks = odbc_result($query2, $a)))
die("Couldn't get result") ;
echo "<TR>";
echo "<TD>$track_id</TD>";
echo "<TD><a href='./tracks.php?id=" . $track_id . "'>" . $tracks . "</a>";
echo "</TD></TR>";


echo "</TABLE>"



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