Hello, On Wed, 19 Dec 2001, Lars Torben Wilson wrote:
> Vlad Krupin writes: > > lot of reasons), and we don't have this functionality. Hence, at least > > if parameter to exit() is an int, we should just return the error code, > > *not* print it. > > +1 >From a techincal point of view I totally agree with this. But I also know that it breaks some scripts, IMO, badly coded scripts, but still. I still say +1 for this. > > Jani Taskinen wrote: > > > > >>From manual: > > > > > >"The exit() function terminates execution of the script. It prints > > >status just before exiting. If status is an integer, that value will be > > >used as exit-status." > > > > > >This can be understood in many ways. If the status is integer, > > >it is used as exit-status..but it's not clear that it's ALSO printed out > > >which is simply buggy behaviour. Two ways to fix it then, either update the manual, or fix exit(). I go for the last one then. Ppl who relied on the undocumented feature then, did simply the wrong thing. Derick -- PHP Development Mailing List <http://www.php.net/> To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]
