No, that wont work - unfortunately the purpose of the function is to read
the values from a database then add them to the URL.
So the URL is sent to the function - but the values within the URL will come
from the database which is accessed from within the function.
Thanks,
Abe
----- Original Message -----
From: "DanO" <[EMAIL PROTECTED]>
To: "Abe" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Thursday, January 11, 2001 9:34 PM
Subject: RE: [PHP] Function -> Sending URL's
>
> you are assigning the variable within the function, then calling the
> function with the variable.
>
> this is a variable scoping issue.
>
> try this:
>
> <?
> function testPassVar($url) {
> echo "<a href=\"$url\">Click</a>";
> }
>
> $company = "TEST";
> $url = 'asdfasdf.php3?name='.$company;
> testPassVar($url);
> ?>
>
>
>
> -----Original Message-----
> From: Abe [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, January 11, 2001 1:35 PM
> To: [EMAIL PROTECTED]
> Subject: [PHP] Function -> Sending URL's
>
>
> Hey there,
> this is a strange one - I want to send a URL to a function that includes
> varibles. Those variables should be taken from within the function - as
in
> the example below the link I want is:
>
> asdfasdf.php3?name=TEST , but that is not what I get as you can see.
>
> Does anybody know a way around this - The example is simpler than what I
am
> actually doing and the value of $company must come from the variable.
>
> Thanks,
> Abe
>
>
>
> <?
> function testPassVar($url) {
> $name = "TEST";
> echo "<a href=\"$url\">Click</a>";
> }
>
> $url = 'asdfasdf.php3?name=$company';
> testPassVar($url);
> echo "This is a $name";
> ?>
>
>
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