Re: [PHP] while loop and modulus?

[Ron Wills]

"James, Yz" wrote:

OK, using this code:

<?

echo "<table border=\"0\">\n";
echo "<tr>\n";

$photocount = 0;

while($row = mysql_fetch_array($result)) {
     $smallpic = $row['smallpic'];

 echo "<td>$smallpic</td>\n";

 if (($photocount % 3) == 2) {
     echo "</tr>\n<tr>\n";
 }
 $photocount++;

     }
 

This should fill in the remaining cells you need. You might have to tinker with it a bit to fit your code though. Good luck :-)

for ($cnt = 0; $cnt < $phonecount % 3; $cnt++)
    echo "<td>&nbsp;</td>
 

 
echo "</tr>\n";
echo "</table>";

?>

And 8 photos in the table, I'm getting this output:

<table border="0">
<tr>
<td>sm982438092.gif</td>
<td>sm982437452.gif</td>
<td>sm982439016.gif</td>
</tr>
<tr>
<td>sm982529915.gif</td>
<td>sm983222652.gif</td>
<td>sm983222686.gif</td>
</tr>
<tr>
<td>sm983222868.gif</td>
<td>sm983222919.gif</td>
</tr>
</table>

Great, except it's missing an end cell, and after a few hours fiddling about
with code last night, I still didn't get any further in working out how I
was going to echo a table cell even if data's missing.  So, any help would
be appreciated.

Apologies for what're probably "easy" questions.  I slog away at work all
day, come back hoping to get something productive done on this, and the
ol'brain won't take it.  Frustrating, to say the least.

James.

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--
209 Media <http://www.209media.com>
Ron Wills <[EMAIL PROTECTED]>
Programmer
 

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