doesn't work but also doesn't give any errors, I will try to explain what I
am trying to do:
I am trying to remove the header and footer to create a "printer friendly
page" with just the content, here's what my pages look like, I need to
remove header and footer when they visit: file.php?action=print
<?php
include("../config.php");
if($_GET[action] == "print")
{
$header = str_replace('include("$header");', '', $header);
$footer = str_replace('include("$footer");', '', $footer);
}
include("$header");
?>
// html
<?php include("$footer"); ?>
cheers,
- Sebastian
----- Original Message -----
From: "John Gray" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Saturday, March 15, 2003 12:31 AM
Subject: [PHP] Re: str_replace
| $footer = str_replace('include("$header");', '', $footer);
|
| The way you have it now, you're telling PHP to first include the file
| named by the variable $header, then do an str_replace on the result; but
| the parser is going to fail on that first semi-colon, and that's not
| what you want to do anyway (as I understand it). Put the line you want
| to replace inside single quotes (as above) and PHP won't attempt to
| parse it, it'll just treat it as a string literal. Hope this helps, hope
| it makes sense.
|
| - john
|
| Sebastian wrote:
| > This may seem weird:
| >
| > How do I str_replace an include function?
| >
| > I want to replace this line: include("$header");
| >
| > with nothing ..
| >
| > something like this:
| >
| > $footer = str_replace(" '. include("$header"); .' ", "", $footer);
| >
| > I get errors, any ideas?
| >
| > cheers,
| > - Sebastian
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