You could try this instead:
Checklogin.php
if (!$name || !password) {
$message = $enter_info;
}
if ($message){
include ("login.php");
echo $message;
exit;
}
But the way you had it should work, you might just need to
global $message;
right before the echo in login.php in case it is inside a function
----- Original Message -----
From: "Beauford.2002" <[EMAIL PROTECTED]>
Newsgroups: php.general
To: "PHP General" <[EMAIL PROTECTED]>
Sent: Thursday, March 27, 2003 3:47 PM
Subject: Include Question
> Hi,
>
> First, I fixed my other problem of the stack overflow by moving the files
> back to the root directory (although I would rather have them in a login
> directory). Anyway, I have a question regarding the include function. I
have
> a login script in a file called login.php - in this file it includes
> checklogin.php and loginerrors.php. If the user inputs an incorrect login
I
> assign $messages the appropriate error from loginerrors, then I re-include
> login.php where I want to show the error message, but no matter what I do
> the error message will not show up.
>
> Example.
>
> Login.php ....
>
> Enter your Name:
> Enter Your Password:
> if ($message) { echo $message; }
>
> Checklogin.php
>
> if (!$name || !password) {
> $message = $enter_info;
> include ("login.php");
> exit;
> }
>
> Any help is appreciated.
>
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
