Chris Boget wrote:
function blah() { //global $GLOBALS; echo 'Globals: <pre>'; print_r( $GLOBALS ); echo '</pre>';
}
As it is shown above, with the 'global $GLOBALS' line commented out, the print_r() works and shows all the currently defined variables and their corresponding values. However, if I declare $GLOBALS as global, nothing gets printed out.
Why?
the global $GLOBALS directive is the equivalent of this PHP code:
$GLOBALS = &$GLOBALS['GLOBALS'];
$GLOBALS does not contain a reference to itself, so you are essentially setting $GLOBALS to refer to nothing! I'm not sure it is a great idea ot allow this, perhaps the internals folks can answer on that one.
Wouldn't the 'global $GLOBALS' line be more or less redundant in most cases? Because $GLOBALS is a superglobal (though, it isn't really)? Why would it affect whether or not $GLOBALS actually has
It appears that $GLOBALS is not a superglobal because a superglobal always has an index in the $GLOBALS array.
While I'm on this subject, why isn't $GLOBALS always a superglobal? For example, this doesn't work:
function innerFunc() {
echo $GLOBALS['blah'];
}
function outerFunc() {
innerFunc();
}
$blah = 'bob'; outerFunc();
Nothing gets echoed from innerFunc(). Why? If anyone can offer any insight as to what is going on, I'd be ever so appreciative.
This code worked for me, I saw "bob." Did you post the example you meant to?
Greg -- phpDocumentor http://www.phpdoc.org
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