On Wednesday 21 January 2004 07:10, Bill Green wrote:
> for ($y=$curr_year; $y < $range; $y++) {
> echo "<option value={$y}>".$y."</option>\n";
> }
>
> When I check for errors:
> $curr_year = 2004
> $curr_year is an integer
> $range = 10
> $curr_year + $range = 2014
> $y = 2004
$y < $range
Do the substitution and what do you get?
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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