Yeah, my solution so far has been to check the last modified time of the session file and then go from there. If the modified time is > then time permitted, then that file is removed and the user's session is rendered null and void. What I am doing is allowing a variable X number of user's to simultaneously log-in under the same user/pass combo (account), and the problem I face is, if none of the user's logs-out, then how will I determine when to pop an inactive account off the stack. Good times.. thanks guys
Christian "Rob Adams" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > "Christian Calloway" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] > > Yeah thats pretty much what I have concluded. I was absolutely sure there > > would be a way to check if a session was still active, but I guess not > :-(. > > Thanks though > > It depends on your definition of 'active.' If you wanted to see if the > specific session you are looking at has been used in the past half hour, > that is possible. Following is a script I've used to help debug sessions > sometimes. While it's not what you're asking for, it may help you figure > out how to do it. It may need tweaking to run on your server. > > <? // sessioninfo.php > $path = ini_get('session.save_path'); > if (isset($_GET['empty'])) > { > if (isset($_COOKIE['PHPSESSID'])) > setcookie('PHPSESSID', ''); > header('Location: sessioninfo.php'); > } > if (count($_GET) == 0) > { > echo "<br>Path: $path<br>"; > $dir = dir($path); > while ($file = $dir->read()) > { > $file_arr[$file]['time'] = filectime($path . '/' . $file); > $file_arr[$file]['size'] = filesize($path . '/' . $file); > } > $dir->close(); > asort($file_arr); > echo '<table > border=1><tr><th>Time</th><th>Size</th><th>SessionID</th></tr>'; > foreach($file_arr as $fname => $data) > { > if ($fname == '.' || $fname == '..') > continue; > $ftime = date('Y-m-d G:i', $data['time']); > $sessid = substr($fname, 5); > echo "<tr><td>$ftime</td><td>{$data['size']}</td><td><a > href=\"?sessionid=$sessid\">$fname</a></td></tr>"; > } > echo '</table>'; > } else if (isset($_GET['sessionid'])) { > setcookie('PHPSESSID', $_GET['sessionid']); > header('Location: sessioninfo.php?show=true'); > exit(); > } else { > session_start(); > echo '<pre>'; > print_r($_SESSION); > print_r($_GET); > echo '</pre>'; > } > ?> > > > > > > > Christian > > > > "Larry Brown" <[EMAIL PROTECTED]> wrote in message > > news:[EMAIL PROTECTED] > > > I don't know of a function, but you could possibly read the directory > > where > > > the SID files are stored. I use sessions a lot; however, I've not tried > > to > > > accomplish this. I don't know if by default you can read the SID > > directory > > > from a script or if this is blocked for security reasons or not. If > not, > > > you could read the directory, match the SIDs from your list and go from > > > there. There is no way of knowing if the person is still actively using > > the > > > SID this way though. > > > > > > Larry. > > > > > > -----Original Message----- > > > From: Christian Calloway [mailto:[EMAIL PROTECTED] > > > Sent: Monday, February 09, 2004 9:28 AM > > > To: [EMAIL PROTECTED] > > > Subject: [PHP] check if user session exists > > > > > > > > > Given a set of session id's, is it possible to query whether a given > > session > > > exists. I am not talking about the current user session, instead I am > > > referring to any and all possible user sessions currently in play. For > > > example: > > > > > > if (session_exists($sessionId)) doSomething(); > > > > > > I've been looking very hard for this one and haven't found an answer at > > all. > > > Any ideas? > > > > > > -- > > > PHP General Mailing List (http://www.php.net/) > > > To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
