Re: [PHP] load a URL and trap output

[Roger Spears]

Tom Meinlschmidt wrote:


simple use fopen() or file()

as $fp = fopen("http://somedomain/some.url?blablah","r";);

and read via fread()

 

Then I replied with:

Perhaps I was mistaken, I thought:

$fp = fopen("http://somedomain/some.url?blablah","r";);
fread();
Would just return the actual HTML code of the page and NOT the results 
of running the page?.?.?.?.?

I will test it out and see.  Thank you for your suggestion!

Hello All,

It seems fopen() did not work.  However, it did stop the FORBIDDEN 
message I was receiving.  So I think I'm on the right track.  Here's 
what I tried...

$filename = "actual URL";

$fd = fopen("$filename", "r");
$contents = fread($fd, $filename);
fclose($fd);
print strlen($contents);
print "<p>".$contents;
I can open the URL, that works ( fopen() ).
I've tested out the fread(), file(), fgets(), and file_get_contents 
functions.  Nothing works.
I can close the URL, that works ( fclose() ).

With each attempt, I get 0 for the strlen of $contents and nothing else 
prints out.

I also tried adding this to the script right before fopen:
ini_set('allow_url_fopen','1');
That didn't work either...

Any idea(s) on what I'm doing wrong?  I'm using php 4.3.3 and I believe 
it's Apache 1.3

Thanks,
Roger
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