> Why does this fail when using an array element, but using a variable will > work? Why should PHP care what the variable is I'm trying to store into? > > list($bar['CompanyCode'], $CompanyDB) = mysql_fetch_row($sth);
Wouldn't it be easier to simply do: $result = mysql_fetch_row($sth); And then work with the $result array? If your DB indexes are listed as CompanyCode and CompanyDB, then use: $result = mysql_fetch_array($sth); Then you have your variable names like you want: $result['CompanyCode'] and $result['CompanyDB'] -- --Matthew Sims --<http://killermookie.org> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
