if youdo if($var) { }
and var doesnt exist at all, thats an error. if(isset($var)) { } will test to see if $var exists, but will not test the value of var, so $var could be blank... Jason "Pat" <[EMAIL PROTECTED]> wrote: > > So, you have to know, first, what is your meaning of your empty variabe: > null, 0, "", array()? > > For example, "$var = 0;", empty($var) says true... but you? > > "Jason Davidson" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] > > as suggeted the isset and empty functions are usefull, > > or if you know it may be set, but could be empty, how about just > > if($variable) { > > > > } > > > > that is the same as > > if($var == "") > > > > "Chris Mach" <[EMAIL PROTECTED]> wrote: > > > > > > What is the best way to determine if a variable is empty? > > > > > > I have a feeling there is a better way than the way I'm doing it now... > > > > > > if ($variable == "") > > > > > > > > > --- > > > Outgoing mail is certified Virus Free. > > > Checked by AVG anti-virus system (http://www.grisoft.com). > > > Version: 6.0.766 / Virus Database: 513 - Release Date: 18-Sep-2004 > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php