Hi
if you want the *rest of the string from the nth <br>*, I think
'preg_match_all' with PREG_OFFSET_CAPTURE can help you (see
http://www.php.net/manual/en/function.preg-match-all.php)
You could do something like:
<code>
$string = "one<br>two<br>three<br>four<br>five";
$count = preg_match_all('/<br>([^<]+)/', $string, $out,
PREG_OFFSET_CAPTURE);
</code>
and you will have an array of 2 arrays, where the first one contains the
full pattern matches and the second one contains arrays for each string
matched *and the starting offset* of that string.
Therefore, to know where the 2nd <br> ends (so we would get 'three') all you
have to do is:
$out[1][1][1] => 14
Just my .2 euros...
Silvio Porcellana
----- Original Message -----
From: "Brian Dunning" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, September 22, 2004 5:54 PM
Subject: [PHP] Split haystack at nth occurrence of needle?
> I've been RTFMing for about an hour and I can't find a string function
> to split haystack 'one<br>two<br>three<br>four<br>five' at the nth
> occurrence of needle '<br>'. strpos gives me the position of the first
> needle, and strrpos gives me the position of the last needle. But I'm
> looking for the position of one of the in-between needles, so that I
> can use substr() to trim everything from there on. What very obvious
> function was I unable to find in the manual?
>
> Thanks,
>
> - Brian
>
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