Reinhart,


<?php for($i = 0; $i < mysql_num_rows($result)-1; $i++) { $row = mysql_fetch_object($result); echo '"'.$row->picture_url.'"'; if($i <= mysql_num_rows($result)-2) { echo ','; } } ?>

Here is how I do in my developments.

Regards,
Bruno B B Magalh„es

On Nov 7, 2004, at 8:44 AM, Reinhart Viane wrote:

Hey all,
Hope some of you also work on sundays :)

I have a little javascript which displays a images (with previous / next
thing)
Now, i populate the javascript array with an php array:


<SCRIPT LANGUAGE="JavaScript">

<!-- Begin
NewImg = new Array (
<?php
while($row = mysql_fetch_object($result)){
echo "\"".$row->picture_url."\",";
}
?>
"../pictures/7_stripper3.jpg",
"../pictures/7_stripper2.jpg"
);
var ImgNum = 0;
var ImgLength = NewImg.length - 1;
...
</script>

As you can see i echo the url of the picture.
After each picture url there needs to be a ','
But not after the last picture.
At this moment all pictures have the ',' after there url, even the last
one.
Any way to determine if the url is the url of the last picture and thus
not printing a ',' behind that last one?

Thx in advance,

Reinhart

  _____

Reinhart Viane
<mailto:[EMAIL PROTECTED]> [EMAIL PROTECTED]
Domos || D-Studio
Graaf Van Egmontstraat 15/3 -- B 2800 Mechelen -- tel +32 15 44 89 01 --
fax +32 15 43 25 26



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