On Mon, April 25, 2005 10:54 am, Jason Barnett said:
> Jay Blanchard wrote:
>> [snip]
>> Can PHP generate an array based on file names in a folder?
>>
>> For example, if I have a folder called "photos" that includes three
>> files -- tree.jpg, house.jpg and boat.jpg -- can PHP "look" at the file
>> and generate a variable $photos= array ("tree", "house","boat"). Any
>> ideas for how to "sniff" out a folder to determine how many files are in
>> it and then create an array with the file names in it?
>> [/snip]
>>
>> Start with http://www.php.net/readdir
>
> Yep.
>
> <?php
>
> $dp = fopen('/path/to/dir', 'r');This should be http://php.net/opendir not fopen. Though fopen might work on some platforms, I guess maybe... > while(false !== $files[] = readdir($dp)) {} This is a bit terse, and will include "." and ".." (with opendir) which you probably don't want... while ($file = readdir($dp)){ if ($file != '.' && $file != '..'){ $files[] = $file; } } > closedir($dp); > $str = implode('', $files); > var_dump($str); > > ?> > -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
