Mark,
Back to basics budy!!
> 25 if ($myrow = mysql_fetch_array($result)); {
should be
> 25 if ($myrow = mysql_fetch_array($result)) {
Note that extra semicolon?
Prathap
---------- Original Message -----------
From: Mark Sargent <[EMAIL PROTECTED]>
To: php-general@lists.php.net
Sent: Tue, 26 Apr 2005 16:01:24 +0900
Subject: [PHP] Parse error: parse error, unexpected T_ELSE
> Hi All,
>
> again, I'm following an example from webmonkey,
>
> http://webmonkey.wired.com/webmonkey/99/21/index3a_page2.html?tw=programming
>
> and I'm changing only what's relevant to me. I haven't altered the
> code basics, though. But I get the error regarding "else". I don't
> see what it is. Anyone..? Cheers.
>
> Mark Sargent.
>
> *Parse error*: parse error, unexpected T_ELSE in
> */var/www/html/phpmysqltable.php* on line *41*
>
> 25 if ($myrow = mysql_fetch_array($result)); {
> 26
> 27 echo "<table border=1>\n";
> 28
> 29 echo "<tr><td>Product Name</td><td>Product Model
> Number</td><td>Product
> 30 Serial Number</td></tr>\n";
> 31
> 32 do {
> 33
> 34 printf("<tr><td>%s</td><td>%s</td><td>%s</td></tr>\n",
> $myrow[product_name], $myrow[product_model_number],
> 35 $myrow[product_serial_number]);
> 36
> 37 } while ($myrow = mysql_fetch_array($result));
> 38
> 39 echo "</table>\n";
> 40
> 41 } else {
> 42
> 43 echo "Sorry, no data is available for that request";
> 44
> 45 }
>
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