[PHP] date() problem

[Ryan A]

Hi,

I'm confused, this should give me the age as 17 instead of 16...but it does
not...any ideas why?

<?php print date("Y:m:d");
$age="1988-07-06";

$day1=strtotime($age);
$day2 = strtotime(date("Y-m-d"));
$dif_s = ($day2-$day1);
$dif_d = ($dif_s/60/60/24);
$age = floor(($dif_d/365.24));

echo $age;
?>

Thanks,
Ryan

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