At 7:21 PM -0500 6/18/06, Rob W. wrote:
>I got the previous question answered, Now here's my next problem.
>
>With the numbers displaying correctly again I got:
>
>1
>2
>3
>4
>5
>6
>7
>10
>11
>12
>13
>14
>15
>16
>17
>18
>19
>20
>21
>22
>25
>
>listed in that order in the database
>
>Now i'm trying to figure out how to write a syntax saying that if like number
>8 isnt listed, display it.
>
>I've tried doing a
>
>if ($count != $data) {
> echo "$data";
>}
>$count++;
>
>But when I get to like id number 9 it dont work right because the next entrie
>is displayed as 10 in the db. So that's my problem is to try and display only
>them numbers that are not in there. I have also tried putting the numbers in
>to an array and matching from there but it still come's up as the same as
>above.
>
>- Rob
Rob:
Why?
If you want to show the number of records in your dB, then just show them. If
you want a counter, then add a counter but don't list the id number. Besides,
why would you want to anyway?
tedd
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