Usen this:
echo ³not found²;
break;
""Rahul S. Johari"" <[EMAIL PROTECTED]> escreveu na mensagem
news:[EMAIL PROTECTED]
Ave,
code:
$db = dbase_open("osm.dbf", 0);
if ($db) {
$record_numbers = dbase_numrecords($db);
for ($i = 1; $i <= $record_numbers; $i++) {
$row = dbase_get_record_with_names($db, $i);
if ($row['PHONE'] == $thekey) {
echo ³found²;
}
else {
echo ³not found²;
break;
}
}
}
The loop reads each row in the database, and checks whether it matches
$thekey or not. If it does, it prints ³found², if it doesn¹t, it prints ³not
found². But this happens for ³each row² in the database. So if there are 100
records, and the program does find a match, I¹ll get 99 ³not found² printed,
and one ³found² printed.
I can easily put an ³exit;² after my echo in the else(), but then it stops
the loop, and doesn¹t go any further.
What do I have to do to get results if the phone matches, print nothing for
rows where it doesn¹t match, but give one single ³not found² if the phone
number does not exist in the database?
The logic is just failing me at this point.
Rahul S. Johari
Supervisor, Internet & Administration
Informed Marketing Services Inc.
500 Federal Street, Suite 201
Troy NY 12180
Tel: (518) 687-6700 x154
Fax: (518) 687-6799
Email: [EMAIL PROTECTED]
http://www.informed-sources.com
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