"Mark Cain" <[EMAIL PROTECTED]> wrote in message
9cufuv$s20$[EMAIL PROTECTED]">news:9cufuv$s20$[EMAIL PROTECTED]...
>
> Two things:
> 1) Why does the code below produce this result?
> 2) How do I assign to an multidimensional array with dynamic keys?
>
> Here is the test code:
>
> $first = "Elementary";
> $second = "Middle";
>
> echo "before assignment:<BR>";
> echo "first = $first<BR>"; // prints: first = Elementary
> echo "second = $second<P>"; // prints: second = Middle --- looks as
> expected here
>
>
look, before the assignment:
0. both $first and $second are string-type variables.
> $first[$second] = "pass";
1. In this case the brackets mean to index a character of the string (like in C), but
2. $second is converted into int because of using as a string-index,
the integer value of $second ("Middle") equals to 0. (how can you convert it in
any other way?)
3. Things getting clearer... the your assignment says:
- the 1st character of string $first let be "pass",
there is no room any other character, but "p". (because of PHP think you'd like to
change the 1st char only.)
4. so: "Elementary" ---> "plementary"
>
>
> echo "After Assignment:<BR>";
> echo "first = $first<BR>"; // prints: first = plementary --- what is
> this ????!!
> echo "second = $second<BR>"; // prints: second = Middle
> echo "$first[$second]"; // prints: P
what you want is the following - i think (i'm not familiar with perl at all):
$first = array($first, $second); what this produces is can be tested with
var_dump($first) not with echo, by the way
var_dump($first);
This is a one-dimensional array with two entries.
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