Richard Lynch wrote:
  $query = "select tag, popular from (select tag, count(*) as popular
from entry_tag group by tag order by popular desc limit 100) as p
order by tag";

I'm no expert, and I have no way to test this, but the following should work and gets shot of the sub-select...

select tag, count(1) as popular
from entry_tag
group by tag
order by popular desc, tag
limit 100

-Stut

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