On 6/13/07, Dan Shirah <[EMAIL PROTECTED]> wrote:
Okay, I know this has got to be easy but it's not working any way I try it.
When a record is selected it opens up a new page. My query will display the
specific results based on the type of record selected. There can be
multiple values in each if. However I am having a brain fart in my if
statement assigning the multiple values.
Here is my if statement:
if ($type == 'T','D','L' {
$get_id.=" payment_request WHERE id = '$payment_id'";
}
However this does not return ant results.
I've tried if ($type = array('T','D','L'), if ($type == array('T','D','L'),
if ($type == 'T,D,L'), if ($type == 'T' or 'D' or 'L'
I also looked in the PHP manual for examples of if's and didn't find any
help.
I can get it to work if I create a seperate if statement for each type
condition but i would prefer to not duplicate my code just to add a seperate
$type
Dan,
Are you trying to do this?
<?
if ($type == 'T' || $type == 'D' || $type == 'L') {
$get_id.=" payment_request WHERE id = '$payment_id'";
}
?>
--
Daniel P. Brown
[office] (570-) 587-7080 Ext. 272
[mobile] (570-) 766-8107
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
