Re: [PHP] Transfer query result to another script

[C.R.Vegelin]

Hello David, Jim,

Thanks for your response.
Yes, I do have session_start() at the top of Report.php.
The reason for having the query on a different page than the result
is that the result may be sent to various output types / scripts.
I will change my code as follows:

Engine.php
-------------
$result = mysqli_query($connect, $myquery);
if (!$result) error ...
if (mysqli_num_rows($result) == 0) error ...
// fill $_SESSION['results'] with query result
switch ($output)
{
   case "HTML": header("Location: Report.php"); break;
   case "CSV": ...
   case "XML": ...
   case "PDF": ...
}

Thanks again for your advice.
Regards, Cor
  ----- Original Message ----- 
  From: David Giragosian 
  To: C.R.Vegelin ; php-general 
  Sent: Thursday, November 01, 2007 5:23 PM
  Subject: Re: [PHP] Transfer query result to another script


  On 11/1/07, C.R.Vegelin <[EMAIL PROTECTED]> wrote: 
    Hi All,

    Q: Is it possible to transfer a query result to another script ?
    For example with (fragments of) the following 2 scripts: 

    Engine.php
    ----------------
    $result = mysqli_query($connect, $myquery);
    if (!$result) error ...
    if (mysqli_num_rows($result) == 0) error ...
    $_SESSION['result'] = $result;
    header("Location: Report.php");

    Report.php
    ----------------
    $result = $_SESSION['result'];
    while ($row = mysqli_fetch_array($result)) ...

    This last line gives "Couldn't fetch mysqli_result". 
    Is this because the result set is local to Engine.php ?

    TIA, Cor

  Cor,

  Do you have session_start() at the top of Report.php?

  The manual shows an example of passing a php created class object using a 
session variable, with the caveat of needing to include the class definition on 
each page.

  It may be different for a mysql result object though.

  Why do you need the query on a different page than the result?

  David