i am not sure what u want to do, for this case you need to tell us
about your database table
structure. i quess you have table like this.. assume the table name is
table1 and there are ten
column in it file1..file10 respectively
|table1 |
|member_id |
|file1 |
|file2 |
|file3 |
| : |
|file10 |
while($row = mysql_fecth_array($sql_result))
{
echo display_file($row['file1']);
echo display_file($row['file2']);
:
echo display_file($row['file10']);
}
function display_file($filename)
{
if file not exist or null etc
return add file here link
else
return display file, delete file
}
this is the idea. of course maybe not what you want, unless you can tell us what
really you want to do or what you got..
On 6/17/08, Wolf <[EMAIL PROTECTED]> wrote:
> Richard Kurth wrote:
>> Wolf wrote:
>>> Richard Kurth wrote:
>>>> Could you please give me an idea where to start looking
>>>>
>>>> while($row=mysql_fetch_array($sql_result)){
>>>>
>>>> if ($row["number"]==1) {
>>>> <tr>
>>>> <td> File 1</td>
>>>> <td>This is the file</td>
>>>> <td>Delete</td>
>>>> </tr>
>>>> }else{
>>>> <tr>
>>>> <td>File1</td>
>>>> <td></td>
>>>> <td>Add</td>
>>>> </tr>
>>>> }
>>>>
>>>> }
>>>
>>>
>>> What is the query being executed?
> <!-- SNIP -->
>
>>>
>> This is the query being executed
>> $sql = "SELECT * FROM table WHERE members_id =" . $_SESSION["members_id"];
>> $sql_result = mysql_query($sql) or die(mysql_error());
>>
> That still pretty much tells me nothing.
>
> Does your table named table exist?
> Does your script connect or error?
> What DOES output to your screen?
> Does the schema for your table contain numbers?
>
> What happens when you use $row['number']?
>
> Or are you just hoping for someone to write your code?
>
> As written, your code will fail due to having PHP interspersed with HTML
> code. As such, you either need to echo or exit out of the PHP areas and
> then continue.
>
> Wolf
>
>
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