On 3/12/2009 9:39 AM, "TG" <tg-...@gryffyndevelopment.com> wrote:
> $currmonth = date("m");
>
> for ($i = 1; $i <= 11; $i++) {
> $m[$i] = date("m/d/y"), mktime(0,0,0,$currmonth-$i, 1, 2009));
> }
>
> Something like that. mktime() is remarkably flexible. If you start on
> month 3 and you subtract 5, you get month = -2. So that would be
> -2/1/2009, which mktime will translate to 11/1/2008.
>
> This is totally off the top of my head, but you get the idea. Works with
> days and years too. Sometimes it's useful when going backwards and not
> sure how many days the previous month had (without doing another call to
> find out).
>
> -TG
SOLVED - Thanks so much Andrew & TG
>From your examples - I was able to create this working table going back 2
years - thanks again!
============
<table border="1" cellspacing="2" cellpadding="2">
<tr>
<td>Dates</td>
</tr>
<?php
$currmonth = date("m");
$curryear = date("y");
$i = 0;
do { ?>
<tr>
<td><?php
$m[$i] = date("m/d/y", mktime(0,0,0,$currmonth-$i, 1, $curryear));
echo $m[$i].'<br />';
$i++ ?>
</td>
</tr>
<?php } while ($i < 25); ?>
</table>
--
Thanks - RevDave
Cool @ hosting4days . com
[db-lists 09]
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