On 3/14/2009 5:13 PM, "Christian Wagner" <[email protected]> wrote:
> Hi,
> I would select all items with a single select.
>> SELECT name,model, condition (etc....) FROM inventory
>
> Then i'll iterate through the resultset and store them in an array like this
>
> $items = array();
> while($row = next())
> {
> // Gives the total amount of Models
> $items[$row['model']] = $counter++;
> // Stores the condition of a single item of a model
> // $items[$row['model']] makes sure, that the single item
> // will be stored at the correct position
> //
> $items[$row['model']][$row['id']] = $row['condition'];
> }
Here's my query... (no group by - right?)
mysql_select_db($database_test, $ test);
$query_getall = "SELECT id, model,condition FROM inventory ORDER BY model
ASC";
$getall = mysql_query($query_getall, $test) or die(mysql_error());
$row_getall = mysql_fetch_assoc($getall);
$totalRows_getall = mysql_num_rows($getall);
Thanks for your help Christian,
I guess my 'newbie' is showing ... Because I'm having trouble getting this
to work...
1 - on this line I get : Warning: Wrong parameter count for next() in
/Libr...
while($row = next())
- I tried this - with no errors
while($row = mysql_fetch_assoc($getall));
// not sure if it's right?
--------------
2 - Then got error here: Warning: Cannot use a scalar value as an array in
/Library/WebServer
$items[$row['model']][$row['id']] = $row['condition'];
Q: How can I fix this?
--
Thanks - RevDave
Cool @ hosting4days . com
[db-lists 09]
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