Thanks for your reply, but that is not it. I had already removed it$, slashed it, and no, plus it is working in the others.
Gary "Robert Cummings" <rob...@interjinn.com> wrote in message news:4a3a5e7c.8000...@interjinn.com... > > > Gary wrote: >> The center echo does not show. It will show if I replace $newmort with >> anything else. I have copied the first "if" statement,pasted it in the >> second position, and it works fine. Once I change the var to $newmort, >> it will not show. The third echo shows fine, it is only if I use newmort. >> I have renamed the var from mort1, because I was getting the same thing. >> >> <tr> >> <td>Purchase Price: </td> >> <td> <input name="purchprice" type="text"></td> >> </tr> >> <tr> >> <td>Mortgage Amount: </td> >> <td> <input name="newmort" type="text"></td> >> </tr> >> <tr> >> <td>How long seller has owned property: </td> >> <td> <input name="howlong" type="text" size="4"></td> >> </tr> >> >> >> $newmort=STRIPSLASHES($_POST['newmort']); >> $purchprice=STRIPSLASHES($_POST['purchprice']); >> $howlong=STRIPSLASHES($_POST['howlong']); >> >> if ($purchprice) { >> echo "Purchase Price:$ $purchprice<br />"; >> } >> if ($newmort) { >> echo "Mortgage Amount:$ $newmort<br />"; >> } >> if ($howlong) { >> echo "How Long has seller owned property: $howlong<br /><br />"; >> } > > The $ character is a special character for variable interpolation. You > should be escaping it. with a backslash. > > Cheers, > Rob. > -- > http://www.interjinn.com > Application and Templating Framework for PHP -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
