Your if-statement should be like this:

if(isset($_REQUEST['firstname']) && !empty($_REQUEST['firstname'])) {
Contact info:
Skype: parham-d
MSN: fire_lizard16 at hotmail dot com
email: parham90 at GMail dot com
"Allen McCabe" <> wrote in message
>I created a simple survey for my work website, most of the PHP is on my
> process.php document, which is referenced by a form on a seperate page
> containing the form with the method of "post".
> On my process.php page, the script obtains the field data using the
> $_REQUEST[] function.
> I have a small if statement to check to see if they filled out the
> 'firstname' field, and if they did not, to replace $name with "Sir or
> Madam". Unfortunately, $name always equals "Sir or Madam", wether a value
> for "firstname" was entered or not.
> All the of the other instances of using $_REQUEST[] functions just fine, 
> but
> don't make use of if or isset. Here is the code snippet:
> if(isset($_REQUEST['firstname']) && !empty($RESULT['firstname'])) {
> $name = $_REQUEST['firstname'];
> } else {
> $name = 'Sir or Madam';
> }
> I also tried adding an underscore to $RESULT (I got the code for this from 
> a
> comment on the manual), to make it $_RESULT, but this doesn't seem
> to be a pre-set function, and it still does not make it work. I am 
> guessing
> the user neglected to define $RESULT in his snippet, or I overlooked it.
> Can anyone see any problems with the code?

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