Not quite sure what the question is.

from:
> mysql> select * from table where id='00001';
> +-------+-----+-----+---+
> | 00001 | 123 | 0.0 | C |
> | 00001 | 234 | 0.1 | D |
> | 00001 | 345 | 0.0 | D |
> | 00001 | 456 | 0.1 | C |
> | 00001 | 567 | 0.1 | G |
> +-------+-----+-----+---+

How do we deduce that you would want ID '00003' ?

This conversation would be easier if we gave names to those columns..

 - michael dykman


On Mon, Jul 19, 2010 at 12:36 PM, Ashley M. Kirchner <ash...@pcraft.com> wrote:
>
>    I may be going at this completely wrong but at the moment I'm stuck.  I
> have a DB from a client and need to do several searches on it.  This one
> sentence is important because it's their DB, not mine.  So I can't modify
> the way the DB was created in the first place, I can only work with what I
> have.  And, whatever the solution to this might be, it does NOT have to be
> strictly MySQL, it can also be a PHP solution (which is why I'm sending it
> there as well.)  So, having said that, consider the following table:
>
> +-------+-----+-----+---+
> | 00001 | 123 | 0.0 | C |
> | 00001 | 234 | 0.1 | D |
> | 00001 | 345 | 0.0 | D |
> | 00001 | 456 | 0.1 | C |
> | 00001 | 567 | 0.1 | G |
> | 00002 | 123 | 0.0 | C |
> | 00002 | 234 | 0.1 | D |
> | 00002 | 345 | 0.0 | D |
> | 00003 | 234 | 0.1 | D |
> | 00003 | 345 | 0.0 | D |
> | 00003 | 123 | 0.0 | C |
> | 00003 | 456 | 0.1 | C |
> | 00003 | 567 | 0.1 | G |
> | 00004 | 123 | 0.0 | C |
> | 00004 | 234 | 0.1 | D |
> | 00004 | 345 | 0.0 | D |
> +-------+-----+-----+---+
>
> mysql> select * from table where id='00001';
> +-------+-----+-----+---+
> | 00001 | 123 | 0.0 | C |
> | 00001 | 234 | 0.1 | D |
> | 00001 | 345 | 0.0 | D |
> | 00001 | 456 | 0.1 | C |
> | 00001 | 567 | 0.1 | G |
> +-------+-----+-----+---+
>
>    Now, I have to find other IDs that match the above result.  In the table,
> that would be ID '00003' (and in the entire DB, there may be others as well
> - I need to find all those IDs.)  But, notice how ID 0003 isn't in the same
> order as ID 00001, but the data is still the same.
>
>    So how do I efficiently search through the DB to find other IDs that
> matches the one I need?  I can't imagine doing a for loop selecting each ID
> and comparing their result to the one I'm starting with.  If the DB contains
> thousands upon thousands of rows, that might take a very long time.
>
>    Open to suggestions.
>
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>
>



-- 
 - michael dykman
 - mdyk...@gmail.com

 May the Source be with you.

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