I have a query that may not always return a result for a value, I need
to reflect this with a "0". I am trying to overcome this by doing this
(the keys are ID's):
while ($row = mysql_fetch_row($statusQuery)) {
$cat = array(0=>0,1=>0,11=>0,12=>0,13=>0,14=>0,15=>0,16=>0,17=>0,19=>0);
switch ($row[1]) {
case 0: $cat[0] = $row[0]; break;
case 1: $cat[1] = $row[0]; break;
case 11: $cat[11] = $row[0]; break;
case 12: $cat[12] = $row[0]; break;
case 13: $cat[13] = $row[0]; break;
case 14: $cat[14] = $row[0]; break;
case 15: $cat[15] = $row[0]; break;
case 16: $cat[16] = $row[0]; break;
case 17: $cat[17] = $row[0]; break;
case 19: $cat[19] = $row[0]; break;
}
print_r($cat);
}
Which gives me this:
Array ( [0] => 15547 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0
[15] => 0 [16] => 0 [17] => 0 [19] => 0 )
Array ( [0] => 0 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15]
=> 30 [16] => 0 [17] => 0 [19] => 0 )
The query only return 2 rows:
15 | 30
0 | 15547
What am I doing wrong? Is there a more elegant way to achieve what I want?
Thanks.
--
Paul Halliday
Ideation | Individualization | Learner | Achiever | Analytical
http://www.pintumbler.org
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