On Jul 30, 2010, at 2:36 PM, Paul Halliday wrote:
> I have a query that may not always return a result for a value, I need
> to reflect this with a "0". I am trying to overcome this by doing this
> (the keys are ID's):
>
> while ($row = mysql_fetch_row($statusQuery)) {
>
> $cat =
> array(0=>0,1=>0,11=>0,12=>0,13=>0,14=>0,15=>0,16=>0,17=>0,19=>0);
>
> switch ($row[1]) {
> case 0: $cat[0] = $row[0]; break;
> case 1: $cat[1] = $row[0]; break;
> case 11: $cat[11] = $row[0]; break;
> case 12: $cat[12] = $row[0]; break;
> case 13: $cat[13] = $row[0]; break;
> case 14: $cat[14] = $row[0]; break;
> case 15: $cat[15] = $row[0]; break;
> case 16: $cat[16] = $row[0]; break;
> case 17: $cat[17] = $row[0]; break;
> case 19: $cat[19] = $row[0]; break;
> }
>
> print_r($cat);
> }
>
> Which gives me this:
>
> Array ( [0] => 15547 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0
> [15] => 0 [16] => 0 [17] => 0 [19] => 0 )
> Array ( [0] => 0 [1] => 0 [11] => 0 [12] => 0 [13] => 0 [14] => 0 [15]s
> => 30 [16] => 0 [17] => 0 [19] => 0 )
>
> The query only return 2 rows:
>
> 15 | 30
> 0 | 15547
>
> What am I doing wrong? Is there a more elegant way to achieve what I want?
>
> Thanks.
>
> --
> Paul Halliday
> Ideation | Individualization | Learner | Achiever | Analytical
> http://www.pintumbler.org
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
Paul-
Why not say:
$cat = array();
if(isset($row[1])
{
$cat[$row[1]] = $row[0];
}
print_r($cat);
Regards,
-Josh
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
