I'm going to jump in and throw in my 2 cents...
Have you used dreamweaver?
I would suggest Dreamweaver to any new programmer beginning php/mysql.
It helped me out tremendously in the beginning. I'm not an advanced programmer
with hand coding classes yet, but I can get any job completed for clients with
dreamweaver. Custom content management systems, image galleries from mysql
etc...
Give it a try, It lets you add the the prewritten code and then you can switch
to code view and see whats its doing.
RD
On Nov 20, 2010, at 3:54 PM, Ben Miller wrote:
> Hi,
>
> I'm building a website for a client in which I need to compare their
> products, side-by-side, but only include criteria for which all selected
> products have a value for that criteria.
>
> In my database (MySQL), I have a tables named "products","criteria" and
> "criteria_values"
>
> If I have something like
>
> $selected_product = array("1"=>"Product 1","2"=>"Product 2"...) // All
> products selected for comparison by the user
>
> I need to get only rows from "criteria" where there is a row in
> "criteria_values" matching "criteria.criteria_id" for each $selected_product
> - in other words, if any of the $selected_product does not have a row in
> "criteria_values" that matches "criteria.criteria_id", that criteria would
> not be returned. I hope that makes sense.
>
> I've played around with a few join queries, but none have given the desired
> results. Best I've been able to come up with so far is to query "criteria"
> for each DISTINCT(criteria_id) and then run through each $selected_product
> to make sure each has a criteria_value with a matching criteria_id,
> eliminating any criteria where the number of criteria_values <
> count($selected_product), but this seems pretty inefficient.
>
> Thanks in advance for any help.
>
> Ben Miller
>
>
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