Thanks for your reply
"Deva" <devendra...@gmail.com> wrote in message 
news:aanlktimvycqsi5nejd1lxxaqbqsb+q_onhoc7omgj...@mail.gmail.com...
>I tried your script locally. Its working for me.
>
> On Tue, Feb 22, 2011 at 11:10 AM, Gary <gp...@paulgdesigns.com> wrote:
>
>> Can someone tell me why this is not working?  I do not get an error
>> message,
>> the results are called and echo'd to screen, the count does not work, I 
>> get
>> a 0 for a result...
>>
>>
>>
>> $result = mysql_query("SELECT * FROM `counties` WHERE name = 'checked'") 
>> or
>> die(mysql_error());
>>
>> if ( isset($_POST['submit']) ) {
>> for($i=1; $i<=$_POST['counties']; $i++) {
>> if ( isset($_POST["county$i"] ) ) {
>> echo "You have chosen ". $_POST["county$i"]." <br/>";
>>        }
>>    }
>> }
>>
>> $county_total=mysql_num_rows($result);
>>
>> while($row = mysql_fetch_array($result))
>> {$i++;
>>    echo $row['name'];
>> }
>> $county_total=mysql_num_rows($result);
>> echo "$county_total";
>>
>> echo 'You Have '  .  "$county_total"  .  ' Counties ';
>>
>> ?>
>> --
>> Gary



Thanks for your reply.

I'm curious, how did you try it locally without a database?

I am still getting either a 0 or a 1 for a result.

Gary 



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