On 22/02/11 13:59, Gary wrote:
"Pete Ford"<p...@justcroft.com> wrote in message
news:a4.c0.39221.b3ca3...@pb1.pair.com...
On 22/02/11 05:40, Gary wrote:
Can someone tell me why this is not working? I do not get an error
message,
the results are called and echo'd to screen, the count does not work, I
get
a 0 for a result...
$result = mysql_query("SELECT * FROM `counties` WHERE name = 'checked'")
or
die(mysql_error());
if ( isset($_POST['submit']) ) {
for($i=1; $i<=$_POST['counties']; $i++) {
if ( isset($_POST["county$i"] ) ) {
echo "You have chosen ". $_POST["county$i"]."<br/>";
}
}
}
$county_total=mysql_num_rows($result);
while($row = mysql_fetch_array($result))
{$i++;
echo $row['name'];
}
$county_total=mysql_num_rows($result);
echo "$county_total";
echo 'You Have ' . "$county_total" . ' Counties ';
?>
The first thing I see is that you do
$county_total=mysql_num_rows($result)
twice. Now I'm not to sure, but it is possible that looping over
mysql_fetch_array($result) moves an array pointer so the count is not
valid after the operation... that's a long shot.
But since you are looping over the database records anyway, why not just
count them as you go? Isn't $i the number of counties after all the
looping?
--
Peter Ford, Developer phone: 01580 893333 fax: 01580
893399
Justcroft International Ltd.
www.justcroft.com
Justcroft House, High Street, Staplehurst, Kent TN12 0AH United
Kingdom
Registered in England and Wales: 2297906
Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17
1XS
Peter
Thank you for your reply.
I did notice that I had the $county_total=mysql_num_rows($result) twice. I
had moved and removed it, always getting either a 0 or 1 result.
I put up another test page with
$result = mysql_query("SELECT * FROM `counties` ") or die(mysql_error());
$tot=mysql_num_rows($result);
echo "$tot";
?>
And it worked fine.
I have tried count() as well as mysql_num_rows() but am getting the same
result.
Could you explain what you mean by count them as I go?
Again, Thank you for your reply.
Gary
__________ Information from ESET Smart Security, version of virus signature
database 5895 (20110222) __________
The message was checked by ESET Smart Security.
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Well,
Lets go back to your original code and cut out the decoration:
$result = mysql_query("SELECT * FROM `counties` WHERE name = 'checked'")
$county_total=mysql_num_rows($result);
while($row = mysql_fetch_array($result))
{
echo $row['name'];
}
echo "$county_total";
That code should do pretty much what you want...
But, because you only show the number of records AFTER the loop, you could do:
$result = mysql_query("SELECT * FROM `counties` WHERE name = 'checked'")
$county_total = 0;
while($row = mysql_fetch_array($result))
{
echo $row['name'];
$county_total++;
}
echo "$county_total";
--
Peter Ford, Developer phone: 01580 893333 fax: 01580 893399
Justcroft International Ltd. www.justcroft.com
Justcroft House, High Street, Staplehurst, Kent TN12 0AH United Kingdom
Registered in England and Wales: 2297906
Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17 1XS
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