On 2/23/2011 4:35 AM, Gary wrote:
> "Pete Ford" <[email protected]> wrote in message
> news:[email protected]...
>> This bit?
>>
>> On 22/02/11 22:06, Gary wrote:
>>> for($i=1; $i<=$_POST['counties']; $i++) {
>>> if ( isset($_POST["county{$i}"] ) ) {
>>
>> You loop over $_POST['counties'] and look for $_POST["county$i"]
>>
>> I suspect that there is no field 'counties' in your form, so the server is
>> complaining about the missing index - seems likely that the production
>> server
>> is not showing the error, but instead just giving up on the page.
>>
>> I think the IE7/Firefox browser difference is a red herring: it wasn't
>> actually working in any browser, or the code changed between tests.
>> Remember, PHP is server side and generates HTML (or whatever). Unless you
>> tell the PHP what browser you are using and write PHP code to take account
>> of that (not generally recommended) then the server output is the same
>> regardless of browser.
>>
>> --
>> Peter Ford, Developer phone: 01580 893333 fax: 01580
>> 893399
>> Justcroft International Ltd.
>> www.justcroft.com
>> Justcroft House, High Street, Staplehurst, Kent TN12 0AH United
>> Kingdom
>> Registered in England and Wales: 2297906
>> Registered office: Stag Gates House, 63/64 The Avenue, Southampton SO17
>> 1XS
>
>
> Pete
>
> Once again, thank you for your help.
>
> I was able to get it to work, I did not understand the browser differences
> either, but on my testing server on IE, it worked as I wanted but not on
> anything else. I chopped out most of the code and ended up with this:
>
> if ( isset($_POST['submit']) ) {} else {
> print "<form action=\"phpForm3.php\" method=\"POST\">\n";
> if ($Recordset1) {
> print "<table width=200 border=1>\n";
> print "<th> </th>\n";
> print "<th> State </th>\n"; //2 fields in Counties table, State and County
> print "<th> County </th>\n";
> print "</tr>\n";
> //create table
> $i = 0;
> while ( $row = mysql_fetch_array($Recordset1) ) {
> $i++;
> print "<tr>\n";
> print "<td><input type=\"checkbox\" name=\"county$i\"
> value=\"$row[name]\"></td>\n";
> echo "<td>{$row['state_id']}</td>\n";
> echo "<td>{$row['name']}</td>\n";
> echo "</tr>\n";
> }//end while
> print "</table>\n";
> } else {
> echo("<P>Error performing query: " .
> mysql_error() . "</P>");
> }
> print "<input type=\"hidden\" name=\"counties\" value=\"$i\"/>\n";
> print "<input type=\"submit\" name=\"submit\" value=\"Go\"/>\n";
> }
> ?>
>
> Again, thank you.
>
> Gary
>
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>
> The message was checked by ESET Smart Security.
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>
If you would allow me to show you a little easier way of doing this.
if ( !isset($_POST['submit']) ) {
echo '<form action="phpForm3.php" method="POST">';
if ($Recordset1) {
echo <<<HEADER
<table width=200 border=1>
<tr><th> </th><th> State </th><th> County </th></tr>
HEADER;
while ( $row = mysql_fetch_array($Recordset1) ) {
echo <<<ROW
<tr>
<td><input type="checkbox" name="county[]" value="{$row['name']}"></td>
<td>{$row['state_id']}</td>
<td>{$row['name']}</td>
</tr>
ROW;
}//end while
echo '</table>';
} else {
echo '<p>Error performing query: '.mysql_error().'</p>';
}
echo '<input type="submit" name="submit" value="Go" />';
}
Now, the main thing I want you to see is the line for the country checkbox'es
The county[] turns the submitted values into an array. So, in the processing
script, you would do this.
<?php
...
if ( !empty($_POST['county'])
foreach ( $_POST['county'] AS $id => $name )
echo "{$id} {$name}\n";
...
?>
Hope this clears things up for you a little.
Enjoy.
Jim
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