On 11-02-23 11:48 PM, Ron Piggott wrote:

Is there a way to make this syntax:

$checking_answer = $answer_reference_2;

Equal to:

$checking_answer = $answer_reference_ . ($i + 1);

(where $i = 1)

making $checking_answer take on the value of $answer_reference_2 ?

I am trying to develop a web app quiz and I need to test the users answers.


$checking_answer = ${'answer_reference_'.($i + 1)};


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