On 2/23/2011 8:48 PM, Ron Piggott wrote:

Is there a way to make this syntax:

$checking_answer = $answer_reference_2;

Equal to:

$checking_answer = $answer_reference_ . ($i + 1);

(where $i = 1)

making $checking_answer take on the value of $answer_reference_2 ?

I am trying to develop a web app quiz and I need to test the users answers.


The Verse of the Day
“Encouragement from God’s Word”

Give this a try

# Variable Variables Test

$id_0 = 'zero';
$id_1 = 'one';
$id_2 = 'two';
$id_3 = 'three';

for ( $i=0; $i<4; $i++ ) {
    echo ${'id_'.$i};


Jim Lucas

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