Hey guys here is my code 4: mysql_connect() or die ("Problemas conectandose a la base de datos"); 5: $query="select * from info where FirstName='$FirstName' and 6: LastName='$LastName' and email='$email'"; 7: $result = mysql_db_query("users", $query); *8: $r=mysql_fetch_array($result); ************ 9: $count=$r["count"]; and i follow redcieving this message Warning: Supplied argument is not a valid MySQL result resource in c:\inetpub\wwwroot\PhpAndMysqlTest\test2\reg1.php3 on line 8 thanks for your answers Yassel
[PHP] php- something that i don't understand
Yassel Omar Izquierdo Souchay Tue, 17 Jul 2001 12:11:07 -0700
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