On 1/3/2013 5:22 PM, Marc Fromm wrote:
Thanks Jonathan. I removed the date() syntax function and it works.

From: Jonathan Sundquist [mailto:jsundqu...@gmail.com]
Sent: Thursday, January 03, 2013 2:16 PM
To: Marc Fromm
Cc: Serge Fonville; php-general@lists.php.net
Subject: Re: [PHP] date problem


When you take a date and do a strtotime you are converting it to an int which 
you can compare to each other much easier. So for your above example you would 
be best doing.

$jes = 01/03/2012;

if ( strtotime($jes) < strtotime(WSOFFBEGIN) )
         $error = " MUST begin after " . WSOFFBEGIN . "\n";
On Thu, Jan 3, 2013 at 4:12 PM, Marc Fromm 
<marc.fr...@wwu.edu<mailto:marc.fr...@wwu.edu>> wrote:
Thanks for the reply.

Every example on comparing dates in PHP that I found uses the "strtotime" 
function which I am using.  What other type can I use?

When is this example below supposed to work?

// your first date coming from a mysql database (date fields)
$dateA = '2008-03-01 13:34';
// your second date coming from a mysql database (date fields)
$dateB = '2007-04-14 15:23';
if(strtotime<http://www.php.net/strtotime>($dateA) > 
     // bla bla


From: Serge Fonville 
Sent: Thursday, January 03, 2013 2:05 PM
To: Marc Fromm
Cc: php-general@lists.php.net<mailto:php-general@lists.php.net>
Subject: Re: [PHP] date problem


date returns a string

You should compare a different type for bigger/smaller than


Kind regards/met vriendelijke groet,

Serge Fonville


Convince Microsoft!
They need to add TRUNCATE PARTITION in SQL Server
2013/1/3 Marc Fromm 
I am comparing to dates.

$jes = 01/03/2012;

if ( date("m/d/Y", strtotime($jes)) < date("m/d/Y", strtotime(WSOFFBEGIN)) )
         $error = " MUST begin after " . WSOFFBEGIN . "\n";

I cannot figure out why the $error is being assigned inside the if statement, 
since the statement should be false. 01/03/2012 is not less than 09/16/2012.


And hopefully put quotes around 01/03/2012.

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