I don't think this is correct!
You can't do this:
list($a, $b) = variable!
which is the case in: list($key, list($tag, $data)) = each($array)
you can use: list($key, $value) = each($array)
"D" <[EMAIL PROTECTED]> wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> I am a newbie and having some problems with a function I found in a
script:
>
> while(list($key,list($tag,$data))=each($array))
>
> From what I have read of list(), what I assume is happening here is that
its
> takeing a 2 dimensional array and assigning the key value pairs
accordingly,
> so that I can then work with the data using the $key, $tag, and $data
> variables while it cycles through each item in the array. Is this correct?
>
> If this is correct, which order is the dimension of the array? For example
> if the values of the variables were: $tag = 2 and $key = 1 would it be:
> $array[1][2] or $array[2][1]
>
> I have tried both, and dont get the $data (outside of the while loop I am
> trying to access specific parts of the array). Other thoughts?
>
> Thanks for the help,
>
> Ken
>
>
>
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
