You really shouldn't be storing a PHP variable in your database...

Too easy for a hacker to get some bad PHP into it.

You could mess with maybe.

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----- Original Message -----
From: Mydata <[EMAIL PROTECTED]>
Newsgroups: php.general
Sent: Sunday, September 30, 2001 3:15 AM
Subject: problem about ereg function

> hi,
> I am using ereg funtion to deal with data submmited by form
> detail shown below:
> I am using a form to submit some html code include image path code
> In submitted php page, I want to replace image path code in html code
> (submitted by last page' form), unfortunately the image path code include
> some php variable (eg "imag src ='$phpvaribe'"),I want to use ereg
> to replace image path code by the value I need. but when I use
> fuction try to replace it . but browser show me parsing error . I don't
> how to use eregi_replace() when php varible in string which needed to be
> replaced. Could someone help me. My error code show below:
> eregi_replace("^\"(.)*{$img1_name}\"$","$replacestring",$content)
> remark:the $img1_name is the php variable in the string which needed to be
> replaced

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